In the Young's double slit experiment using a monochromatic light of wavelength λ , the path difference (in terms of an integer n) corresponding to any point having half the peak intensity is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Sol. For half of maximum intensity
2 Ι 0 = Ι 0 + Ι 0 + 2 Ι 0 cos θ
θ (Phase difference) = 
Path difference is 
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